Page 162 - الكيمياء كتاب الطالب للصف 11 الفصل 1
P. 162
a Fa ] £`q z5 0-a c>Va ¿ 1:M w, &a W>a ¿ ² yfy^a
Z C
CH COOC H (l) + H O(l) ⇌ CH COOH(l) + C H OH(l) E ¹C4: ±
3 2 5 2 3 2 5
0.1000 0.1000 0 0 (mol/L) dg±P ± S= R ±
0.0654 0.0654 0.1000 – 0.0654 = 0.0346 0.1000 – 0.0654 = 0.0346 (mol/L) бS ± P; S= R ±
¤S= R ± G= ` ^ C6 ± ±Q< бS ± F C E ¹C4 D ± ¤ ³b2 ±
[ CH COOH C H OH]
][
K = 3 2 5
c [ CH COOC H 5][ H O]
2
2
3
¤E ¹P4 ± C<:=7 E ¹C4: ± d бS ± S= ±R ÎP ± ¤ ³b2 ±
( 0.0346) ( 0.0346)
×
K = = 0.288
c ( 0.0654) ( 0.0654)
×
¤Ð±S ± E ¹C4 c ¯ Ãb R C E = 0 ± ½C=7 ± ´±P Ò ûh ¤ ³b2 ±
) )
( mol/L × ( mol/L
( mol/L ) × ( mol/L )
½C= ³P Ò a T= (K ) Ð d;4 C C Õ 14 C<14 mol/L S= R ± ½C= ´±P Ò d59
c
ÎC K = 0.288 ±Q<
c
E9
¤ÑC ¹ ´C b94: ± ϱP C d ± ^ C6 9 (K ) бS ± F C E:= D ± £
c
H (g) + CO (g) ⇌ H O(g) + CO(g)
2 2 2
.10.00 mol/L § dg±P ± (H (g)) S= R
2
.10.00 mol/L § dg±P ± (CO (g)) S= R
2
.9.47 mol/L § бS ± P; (CO(g)) S= R
¤E= ± E ¹C4:9 CÕ7 Ò C= b M± ` b8 CÕ4 `= Ò»P=< ±Ò `= ÒR =; ± ^ C6
N (g) + 3H (g) ⇌ 2NH (g)
2 2 3
.1 L a: \95 «C Ò d `= Ò»P=< ± ` 0.1 mol Z `= ÒR =; ± ` 0.1 mol X9 _
©Ð±S ± P; `= Ò»P=< ± S= R N= j ^8 d ^ : ÑC ¹ ´¹C4: ± Ô Ð±S ± P; C= b M± ` n mol ÐÛb8
(0.1 – n)
(0.1 – 0.667n) ²
(0.1 – 1.5n) ¶
(0.1 – 0.5n) ¹

