Page 62 - الكيمياء كتاب الطالب للصف 11 الفصل 1
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a Fa     ] £`q  z5 0-a  c>Va  ¿ 1:M w, &a  W>a  ¿ ² yfy^a


                                                                                                                ÎC

                                                         ¤ Û ^'±       ³¹b b: ± (CaO) Ïb=  C8 ± P=  ­ ´„b  ¹P  D  ±   ˜¢

                    E б E C  c9  R<3=  –56.1 c9  2.9 _ 7  C P;        E= b: ± E9 8 ± Э C Õ :9  –Ïb=  C8 ± P=  ­ `  2.9 g d
                    ÏC »M±  `   Û^ M±  ¹P4 ±  Э  0.051693  ¹P4 ±  E  C  ±         56.1 g/mol ÔÒC   Ïb=  C8 ± P=  M

                    ÔÒC   E9 8 ±’ 2  b  ³C24: ± ´C C=  ± d  E b;4: ±
                    N 0   –`=K b;4  `= Ø: » ]  C ¯ ^:   Э D   ±Q  ˜“2.9 g
                                                     ˜0.052 mol



                                                                                                             α@

                     ˜(SiCl ) (IV) Ðb8=9=  ± P »b9  `  340.2 g ` b8   (Cl ) »b98 ± `  284.0 g Z  (Si) Ðb8=9=  ± `  56.2 g ^ C6       Ÿ
                          4                                     2
                                               ˜^ C6  ± E ¹C4  D  ± ˜^ C6 9  dgC=:=8 ± D C;  ± ¹C  ˆ ´C b94: ± ÑQ  ÏP   ±


                                                                                                E=9 8 ± E b : ± E  ; ±

                   Percentage composition E=9 8 ± E b : ± E  ; ± ²C    E=  ; ± E Û»Q ± ^ 8 ±Ò C  DÛ R  E5=j ϱP   ± C;;8:

                                                                                       ˜DÛ R: ± d  `Û=4  R0;4  by mass

                                     D R  d  `=4  R0;  ´„b  ¹P  × E »Q ± E9 8 ±
                               100 ×                                             § (%) E=9 8 ± E b : ± E  ; ±
                                                 D R:9  E= b: ± E9 8 ±



                                                                                                                ÎC

                                             § (%) E=9 8 ± E b : ± E  ; ±   d  ¹b b: ± P P 9  E=9 8 ± E b : ± E  ; ± D  ±   ˜£
                                                                                     .(Fe O ) (III) P P  ± P=  ­ D R
                                 55.8 × 2                                                2  3
                      100 ×                   § 69.9 %
                           (2 × 55.8)  + (3 × 16.0)
                                                                                                           ¤ Û ^'±
                                                                           ¹P  ¹C  ˆ E=gC=:=8 ± E5=0 ± ÏP   ±  ¤› ³b2  ±
                                                                         ˜(Fe O ) `  P ±Ò Îb  d  P P  ± ´„b
                                                                            2  3
                                                                                 (Fe O ) d  P P  2 mol P b
                                                                                   2  3
                                                                          E b : ± E  ; ± D     E ¹C4: ± ÏP   ±  ¤œ ³b2  ±
                                                                                                  ˜E=9 8 ±

                                                                     100(%) ×  D R  d  `=4  R0;  ´„b  ¹P  × E »Q ± E9 8 ±

                                 Fe O  êmA ëÌ x[™w émšdTÐ ‹X                            D R:9  E= b: ± E9 8 ±
                                   2  3
                             zwzœTÐ ‹X 69.9% o—–h ŽcK œw



                                                                                                             α@

                                                        ˜(C H OH) Îb C  ˆ± d  ¹b b: ± Ðb R89  E=9 8 ± E b : ± E  ; ± D  ±
                                                          2  5





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